VLSM Subnetting — Variable-Length Subnet Mask

Scenario

You are designing the IP plan for a small office. You have been assigned the block 192.168.10.0/24 and need to carve it into 4 subnets sized for the following host counts:

| Subnet | Hosts needed | |---|---| | A — Engineering LAN | 50 | | B — Sales LAN | 25 | | C — Server VLAN | 12 | | D — Management VLAN | 5 |

Rules of the game

• Use VLSM — allocate the largest subnet first, smallest last.
• Each subnet must hold at least the required hosts plus the network + broadcast addresses.
• Subnets must be contiguous starting at 192.168.10.0 — no gaps.
• The right pane shows a worksheet to help you compute.

Answer format

Submit your answer as a comma-separated list of CIDR subnets, sorted by starting IP, no spaces:

192.168.10.0/X,192.168.10.Y/X,192.168.10.Z/X,192.168.10.W/X

Example (NOT the right answer — just shape):

192.168.10.0/26,192.168.10.64/27,192.168.10.96/28,192.168.10.112/29

The flag has the shape of a normal subnet list — there is no TC{…} wrapper for analysis labs. Submit the CIDR string itself.

Tip

For each subnet, the prefix length is determined by: 32 − ceil(log₂(hosts + 2)). The +2 accounts for the network and broadcast addresses.